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Above-Average Values

Keep the values that are greater than the average.

Problem

Compute the average of the list, then keep only the values strictly greater than it, in their original order.

Implement above_average(numbers).

Input

numbers: The list of integers.

Output

Return the values above the average (an empty list for an empty input).

Constraints

0 ≤ length ≤ 10,000; -1,000,000 ≤ each value ≤ 1,000,000

Examples

Example 1
Input:
numbers = [1, 2, 3, 4, 10]

Expected output:
expected = [10]
Input:
std::vector<long long> numbers = {1, 2, 3, 4, 10};

Expected output:
std::vector<long long> expected = {10};
Input:
long[] numbers = new long[] {1, 2, 3, 4, 10};

Expected output:
long[] expected = new long[] {10};

Explanation

The average is 20 / 5 = 4; only 10 is greater than 4.

Example 2
Input:
numbers = [5, 5, 5]

Expected output:
expected = []
Input:
std::vector<long long> numbers = {5, 5, 5};

Expected output:
std::vector<long long> expected = {};
Input:
long[] numbers = new long[] {5, 5, 5};

Expected output:
long[] expected = new long[] {};

Explanation

Every value equals the average 5, so none is greater: [].

References

This challenge is adapted for CodeUtility. Follow the statement and constraints above.

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