Problem
Whole numbers divisible by 2 are even; other whole numbers are odd. A number with a fractional part is neither. Zero is even, and negative integers follow the same rule.
Implement number_parity(number).
Input
number: The number to classify.
Output
Return odd, even, or neither as lowercase text.
Constraints
−1,000,000 ≤ number ≤ 1,000,000. The input is finite and has at most two decimal places.
Examples
Input:
number = 14
Expected output:
expected = "even"Input:
double number = 14;
Expected output:
std::string expected = "even";Input:
double number = 14;
Expected output:
string expected = "even";Explanation
14 = 2 × 7, so it is divisible by 2.
Input:
number = 3.5
Expected output:
expected = "neither"Input:
double number = 3.5;
Expected output:
std::string expected = "neither";Input:
double number = 3.5;
Expected output:
string expected = "neither";Explanation
3.5 has a fractional part, so it is neither an odd nor an even integer.
How to approach it
Try on your own first, then open one hint at a time.
Hint 1
First decide whether the input is a whole number, since fractional values are neither odd nor even.
Hint 2
For whole numbers, parity depends on whether division by 2 leaves a remainder.
Hint 3
Remember that zero is even, and negative integers follow the same rule as positive ones.
Expected complexity
O(1) time, O(1) extra space
References
This challenge is adapted for CodeUtility. Follow the statement and constraints above.