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Count Handshakes

Count handshakes when every pair of people shakes hands once.

Lo que aprenderás

  • Count pairs with n × (n - 1) / 2
  • Reason about counting each pair once
  • Replace a loop with a formula

Problema

Ver traducción

Every person shakes hands once with every other person. A handshake between A and B is the same event as one between B and A. Nobody shakes their own hand.

Implement handshake_count(people).

Input

people: The number of people.

Output

Return the total number of distinct handshakes.

Restricciones

0 ≤ people ≤ 1,000,000,000. The answer fits a signed 64-bit integer.

Ejemplos

Ejemplo 1
Entrada:
people = 4

Salida esperada:
expected = 6
Entrada:
long long people = 4;

Salida esperada:
long long expected = 6;
Entrada:
long people = 4;

Salida esperada:
long expected = 6;

Explicación

The pairs are AB, AC, AD, BC, BD, and CD: six handshakes.

Ejemplo 2
Entrada:
people = 1

Salida esperada:
expected = 0
Entrada:
long long people = 1;

Salida esperada:
long long expected = 0;
Entrada:
long people = 1;

Salida esperada:
long expected = 0;

Explicación

One person has nobody else to greet.

Cómo abordarlo

Inténtalo primero por tu cuenta y luego abre las pistas una a una.

Pista 1

Each handshake is just an unordered pair of distinct people.

Pista 2

Count how many pairs can be formed from all people without double-counting.

Pista 3

Be careful that zero or one person means no handshakes at all.

Complejidad esperada

O(1) time, O(1) extra space

Referencias

Este reto está adaptado para CodeUtility. Sigue el enunciado y las restricciones indicadas arriba.

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