Problema
Compute base to the power exponent with recursion: x⁰ = 1, and xⁿ = (x^(n/2))² for even n or x × (x^((n−1)/2))² for odd n. This uses far fewer multiplications than a simple loop.
Implement recursive_power(base, exponent).
Input
base: The base. exponent: The exponent (zero or positive).
Output
Return base raised to exponent.
Restricciones
-10 ≤ base ≤ 10; 0 ≤ exponent ≤ 18
Ejemplos
Entrada:
base = 3
exponent = 5
Salida esperada:
expected = 243
Entrada:
long long base = 3;
long long exponent = 5;
Salida esperada:
long long expected = 243;
Entrada:
long base = 3;
long exponent = 5;
Salida esperada:
long expected = 243;
Explicación
3⁵ = 3 × (3²)² = 3 × 81 = 243.
Entrada:
base = 7
exponent = 0
Salida esperada:
expected = 1
Entrada:
long long base = 7;
long long exponent = 0;
Salida esperada:
long long expected = 1;
Entrada:
long base = 7;
long exponent = 0;
Salida esperada:
long expected = 1;
Explicación
The base case: anything to the power 0 is 1.
Referencias
Este reto está adaptado para CodeUtility. Sigue el enunciado y las restricciones indicadas arriba.