Todos los desafíos
Fácil 0 resueltos 0% de aceptación

Price Decorators

Wrap a base price in discount, tax, shipping and coupon decorators applied in order.

Lo que aprenderás

  • Stack behaviours in layers around a value
  • Apply percentages in the right order
  • Clamp a value so it never goes below zero

Problema

Ver traducción

The decorator pattern adds behaviour by wrapping an object in layers. Each layer here changes the price of the layer inside it.

Start from base_price and apply the decorators in order:

  • discount p: reduce the price by p percent.
  • tax p: increase the price by p percent.
  • shipping a: add a fixed amount a.
  • coupon a: subtract a, but never go below 0.

Implement price_decorators(base_price, decorators).

Input

base_price: The starting price.

decorators: The layers, in the order they wrap the price. Amounts may have decimals.

Output

Return the final price. Answers within 1e-6 are accepted.

Restricciones

0 ≤ base_price ≤ 1,000,000

0 ≤ number of decorators ≤ 100; 0 ≤ p ≤ 100, 0 ≤ a ≤ 100,000

Ejemplos

Ejemplo 1
Entrada:
base_price = 100
decorators = ["discount 10", "tax 8", "shipping 5"]

Salida esperada:
expected = 102.2
Entrada:
long long base_price = 100;
std::vector<std::string> decorators = {"discount 10", "tax 8", "shipping 5"};

Salida esperada:
double expected = 102.2;
Entrada:
long base_price = 100;
string[] decorators = new string[] {"discount 10", "tax 8", "shipping 5"};

Salida esperada:
double expected = 102.2;

Explicación

100 − 10% = 90, plus 8% tax = 97.2, plus 5 shipping = 102.2.

Ejemplo 2
Entrada:
base_price = 20
decorators = ["coupon 25", "shipping 4"]

Salida esperada:
expected = 4.0
Entrada:
long long base_price = 20;
std::vector<std::string> decorators = {"coupon 25", "shipping 4"};

Salida esperada:
double expected = 4.0;
Entrada:
long base_price = 20;
string[] decorators = new string[] {"coupon 25", "shipping 4"};

Salida esperada:
double expected = 4.0;

Explicación

The coupon would take the price below zero, so it stops at 0; shipping then makes it 4.

Cómo abordarlo

Inténtalo primero por tu cuenta y luego abre las pistas una a una.

Pista 1

Apply the layers strictly in the given order.

Pista 2

Percentages are taken from the current price, not the base price.

Pista 3

A coupon can never push the price below 0.

Complejidad esperada

O(number of decorators) time, O(1) extra space

Referencias

Este reto está adaptado para CodeUtility. Sigue el enunciado y las restricciones indicadas arriba.

Aprende de otros

Soluciones de la comunidad

Aún no hay soluciones publicadas. Resuelve este reto para compartir la primera.