Problema
Represent a fraction as [numerator, denominator]. Apply operation to first and second: add, subtract, multiply, or divide. For absolute, use only first. For power, raise first to the integer exponent and ignore second. Return lowest terms with a positive denominator. Normalize zero to [0, 1]. All divisions and negative powers in valid inputs are defined.
Implement rational_arithmetic(operation, first, second, exponent).
Input
operation: The operation name.
first: Two integers representing the first fraction.
second: Two integers representing the second fraction; use [0, 1] when unused.
exponent: The exponent for power; use 0 for other operations.
Output
Return [numerator, denominator] in reduced form with a positive denominator.
Restricciones
operation is add, subtract, multiply, divide, absolute, or power. Both fraction components have magnitude at most 100; denominators are nonzero. −6 ≤ exponent ≤ 6. For divide, second has nonzero numerator. For a negative power, first has nonzero numerator. The 0th power is [1, 1], including 0⁰ by this task’s convention. Values fit signed 64-bit.
Ejemplos
Entrada:
first = [1, 6]
second = [1, 4]
exponent = 0
operation = "add"
Salida esperada:
expected = [5, 12]
Entrada:
std::vector<long long> first = {1, 6};
std::vector<long long> second = {1, 4};
long long exponent = 0;
std::string operation = "add";
Salida esperada:
std::vector<long long> expected = {5, 12};
Entrada:
long[] first = new long[] {1, 6};
long[] second = new long[] {1, 4};
long exponent = 0;
string operation = "add";
Salida esperada:
long[] expected = new long[] {5, 12};
Explicación
1/6 + 1/4 = 2/12 + 3/12 = 5/12, already reduced.
Entrada:
first = [2, 3]
second = [0, 1]
exponent = -2
operation = "power"
Salida esperada:
expected = [9, 4]
Entrada:
std::vector<long long> first = {2, 3};
std::vector<long long> second = {0, 1};
long long exponent = -2;
std::string operation = "power";
Salida esperada:
std::vector<long long> expected = {9, 4};
Entrada:
long[] first = new long[] {2, 3};
long[] second = new long[] {0, 1};
long exponent = -2;
string operation = "power";
Salida esperada:
long[] expected = new long[] {9, 4};
Explicación
A negative exponent inverts the fraction: (2/3)⁻² = (3/2)² = 9/4.
Cómo abordarlo
Inténtalo primero por tu cuenta y luego abre las pistas una a una.
Pista 1
Convert each fraction to a common representation and combine the numerators according to the chosen operation.
Pista 2
After the operation, reduce the result by dividing by the greatest common divisor and make the denominator positive.
Pista 3
Watch special cases like zero results, absolute value, and the power rule’s zero and negative exponents.
Complejidad esperada
O(log n) time, O(1) extra space
Referencias
Este reto está adaptado para CodeUtility. Sigue el enunciado y las restricciones indicadas arriba.