Problema
Ver traducciónThe exponent is numerator / denominator. Raise base_value to that exponent and return the real-valued result. For example, an exponent of 1/3 gives the positive cube root.
Implement real_to_rational_power(base_value, numerator, denominator).
Input
base_value: The positive base.
numerator: The exponent numerator.
denominator: The exponent denominator.
Output
Return base_value raised to numerator / denominator.
Restricciones
0.1 ≤ base_value ≤ 100, with at most two decimal places. −6 ≤ numerator ≤ 6; 1 ≤ denominator ≤ 10. Answers are accepted within absolute or relative error 0.000001.
Ejemplos
Entrada:
numerator = 1
base_value = 8.0
denominator = 3
Salida esperada:
expected = 2.0
Entrada:
long long numerator = 1;
double base_value = 8.0;
long long denominator = 3;
Salida esperada:
double expected = 2.0;
Entrada:
long numerator = 1;
double base_value = 8.0;
long denominator = 3;
Salida esperada:
double expected = 2.0;
Explicación
2 × 2 × 2 = 8, so the cube root is 2.
Entrada:
numerator = -1
base_value = 16.0
denominator = 2
Salida esperada:
expected = 0.25
Entrada:
long long numerator = -1;
double base_value = 16.0;
long long denominator = 2;
Salida esperada:
double expected = 0.25;
Entrada:
long numerator = -1;
double base_value = 16.0;
long denominator = 2;
Salida esperada:
double expected = 0.25;
Explicación
The square root of 16 is 4, and the negative exponent takes its reciprocal, 1/4.
Referencias
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