Problema
Return the list with repeated values removed, keeping the first occurrence of each value in its original order.
Implement remove_duplicates(numbers).
Input
numbers: The list of integers.
Output
Return the list without duplicates.
Restricciones
0 ≤ length ≤ 100,000
Ejemplos
Entrada:
numbers = [3, 1, 3, 2, 1]
Salida esperada:
expected = [3, 1, 2]
Entrada:
std::vector<long long> numbers = {3, 1, 3, 2, 1};
Salida esperada:
std::vector<long long> expected = {3, 1, 2};
Entrada:
long[] numbers = new long[] {3, 1, 3, 2, 1};
Salida esperada:
long[] expected = new long[] {3, 1, 2};
Explicación
Keep 3, 1, then 2; the later 3 and 1 are dropped: [3, 1, 2].
Entrada:
numbers = [7, 7, 7]
Salida esperada:
expected = [7]
Entrada:
std::vector<long long> numbers = {7, 7, 7};
Salida esperada:
std::vector<long long> expected = {7};
Entrada:
long[] numbers = new long[] {7, 7, 7};
Salida esperada:
long[] expected = new long[] {7};
Explicación
Only the first 7 stays: [7].
Cómo abordarlo
Inténtalo primero por tu cuenta y luego abre las pistas una a una.
Pista 1
Keep the first time each value appears and ignore later repeats.
Pista 2
A set or similar lookup helps you decide quickly whether a value was already seen.
Pista 3
Preserve the original order of the first occurrences, not sorted order.
Complejidad esperada
O(n) time, O(n) extra space
Referencias
Este reto está adaptado para CodeUtility. Sigue el enunciado y las restricciones indicadas arriba.