Problema
Bars of width 1 have the given heights. After rain, water collects above each bar up to the lower of the tallest bars on its left and right. Compute the total trapped water. An O(n) two-pointer solution is expected.
Implement trapped_water(heights).
Input
heights: Bar heights from left to right.
Output
Return the total units of water.
Restricciones
0 ≤ length ≤ 200,000; 0 ≤ height ≤ 100,000
Ejemplos
Entrada:
heights = [0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1]
Salida esperada:
expected = 6
Entrada:
std::vector<long long> heights = {0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1};
Salida esperada:
long long expected = 6;
Entrada:
long[] heights = new long[] {0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1};
Salida esperada:
long expected = 6;
Explicación
Water fills the dips: 1 + 1 + 2 + 1 + 1 = 6 units.
Entrada:
heights = [3, 2, 1]
Salida esperada:
expected = 0
Entrada:
std::vector<long long> heights = {3, 2, 1};
Salida esperada:
long long expected = 0;
Entrada:
long[] heights = new long[] {3, 2, 1};
Salida esperada:
long expected = 0;
Explicación
Heights only go down, so water runs off: 0.
Referencias
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