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Factory Production Time

Find the earliest time parallel machines can finish a target number of items.

All machines start at time 0 and work independently. A machine with time t finishes one item after t seconds, another after 2t seconds, and so on. Find the earliest whole second when their combined production reaches the target.

Implement factory_machines(times, target).

Input

times: Seconds needed for one item on each machine.

target: The number of completed items required.

Output

Return the minimum elapsed seconds.

Contraintes

1 ≤ machines ≤ 200,000. Each time and the target are between 1 and 1,000,000,000. The answer fits signed 64-bit.

Exemples

Exemple 1
Entrée :
times = [2, 3]
target = 5

Sortie attendue :
expected = 6
Entrée :
std::vector<long long> times = {2, 3};
long long target = 5;

Sortie attendue :
long long expected = 6;
Entrée :
long[] times = new long[] {2, 3};
long target = 5;

Sortie attendue :
long expected = 6;

Explication

At time 6 the machines have made 3 + 2 = 5 items. At time 5 they have made only 2 + 1 = 3.

Exemple 2
Entrée :
times = [4]
target = 3

Sortie attendue :
expected = 12
Entrée :
std::vector<long long> times = {4};
long long target = 3;

Sortie attendue :
long long expected = 12;
Entrée :
long[] times = new long[] {4};
long target = 3;

Sortie attendue :
long expected = 12;

Explication

One machine completes its third item at 3 × 4 = 12 seconds.

Références

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