Problème
Compute base to the power exponent with recursion: x⁰ = 1, and xⁿ = (x^(n/2))² for even n or x × (x^((n−1)/2))² for odd n. This uses far fewer multiplications than a simple loop.
Implement recursive_power(base, exponent).
Input
base: The base. exponent: The exponent (zero or positive).
Output
Return base raised to exponent.
Contraintes
-10 ≤ base ≤ 10; 0 ≤ exponent ≤ 18
Exemples
Entrée :
base = 3
exponent = 5
Sortie attendue :
expected = 243
Entrée :
long long base = 3;
long long exponent = 5;
Sortie attendue :
long long expected = 243;
Entrée :
long base = 3;
long exponent = 5;
Sortie attendue :
long expected = 243;
Explication
3⁵ = 3 × (3²)² = 3 × 81 = 243.
Entrée :
base = 7
exponent = 0
Sortie attendue :
expected = 1
Entrée :
long long base = 7;
long long exponent = 0;
Sortie attendue :
long long expected = 1;
Entrée :
long base = 7;
long exponent = 0;
Sortie attendue :
long expected = 1;
Explication
The base case: anything to the power 0 is 1.
Références
Ce défi a été adapté pour CodeUtility. Suivez l'énoncé et les contraintes ci-dessus.