Tous les défis
Facile 0 résolus 0 % de réussite

Xavier and He Weight Initialization

Compute the range or standard deviation used to initialize the weights of a layer.

Ce que vous allez apprendre

  • Compute initialization ranges for a layer
  • Choose between Xavier and He
  • Understand why initialization matters

Problème

Afficher la traduction

Weights that start too big or too small make deep networks hard to train. Two standard schemes pick the scale from the layer size, where fan_in is the number of inputs and fan_out the number of outputs:

methodreturns
"xavier_uniform"limit √(6 / (fan_in + fan_out)), weights drawn from [-limit, limit]
"xavier_normal"standard deviation √(2 / (fan_in + fan_out))
"he_uniform"limit √(6 / fan_in)
"he_normal"standard deviation √(2 / fan_in)

Xavier (Glorot) suits sigmoid and tanh layers; He suits ReLU layers.

Implement init_bound(method, fan_in, fan_out).

Input

method: One of "xavier_uniform", "xavier_normal", "he_uniform" or "he_normal".

fan_in, fan_out: The layer's number of inputs and outputs.

Output

Return the limit or standard deviation as a decimal number.

Contraintes

1 ≤ fan_in, fan_out ≤ 100,000

Exemples

Exemple 1
Entrée :
fan_in = 3
method = "xavier_uniform"
fan_out = 3

Sortie attendue :
expected = 1.0
Entrée :
long long fan_in = 3;
std::string method = "xavier_uniform";
long long fan_out = 3;

Sortie attendue :
double expected = 1.0;
Entrée :
long fan_in = 3;
string method = "xavier_uniform";
long fan_out = 3;

Sortie attendue :
double expected = 1.0;

Explication

√(6 / (3 + 3)) = √1 = 1, so weights are drawn from [-1, 1].

Exemple 2
Entrée :
fan_in = 50
method = "he_normal"
fan_out = 10

Sortie attendue :
expected = 0.2
Entrée :
long long fan_in = 50;
std::string method = "he_normal";
long long fan_out = 10;

Sortie attendue :
double expected = 0.2;
Entrée :
long fan_in = 50;
string method = "he_normal";
long fan_out = 10;

Sortie attendue :
double expected = 0.2;

Explication

He only uses fan_in: √(2 / 50) = √0.04 = 0.2.

Références

Ce défi a été adapté pour CodeUtility. Suivez l'énoncé et les contraintes ci-dessus.

Apprenez des autres

Solutions de la communauté

Aucune solution publiée pour l'instant. Résolvez ce défi pour partager la première.