Problème
Whole numbers divisible by 2 are even; other whole numbers are odd. A number with a fractional part is neither. Zero is even, and negative integers follow the same rule.
Implement number_parity(number).
Input
number: The number to classify.
Output
Return odd, even, or neither as lowercase text.
Contraintes
−1,000,000 ≤ number ≤ 1,000,000. The input is finite and has at most two decimal places.
Exemples
Entrée :
number = 14
Sortie attendue :
expected = "even"Entrée :
double number = 14;
Sortie attendue :
std::string expected = "even";Entrée :
double number = 14;
Sortie attendue :
string expected = "even";Explication
14 = 2 × 7, so it is divisible by 2.
Entrée :
number = 3.5
Sortie attendue :
expected = "neither"Entrée :
double number = 3.5;
Sortie attendue :
std::string expected = "neither";Entrée :
double number = 3.5;
Sortie attendue :
string expected = "neither";Explication
3.5 has a fractional part, so it is neither an odd nor an even integer.
Comment l'aborder
Essayez d'abord seul, puis ouvrez les indices un par un.
Indice 1
First decide whether the input is a whole number, since fractional values are neither odd nor even.
Indice 2
For whole numbers, parity depends on whether division by 2 leaves a remainder.
Indice 3
Remember that zero is even, and negative integers follow the same rule as positive ones.
Complexité attendue
O(1) time, O(1) extra space
Références
Ce défi a été adapté pour CodeUtility. Suivez l'énoncé et les contraintes ci-dessus.