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Price Decorators

Wrap a base price in discount, tax, shipping and coupon decorators applied in order.

Ce que vous allez apprendre

  • Stack behaviours in layers around a value
  • Apply percentages in the right order
  • Clamp a value so it never goes below zero

Problème

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The decorator pattern adds behaviour by wrapping an object in layers. Each layer here changes the price of the layer inside it.

Start from base_price and apply the decorators in order:

  • discount p: reduce the price by p percent.
  • tax p: increase the price by p percent.
  • shipping a: add a fixed amount a.
  • coupon a: subtract a, but never go below 0.

Implement price_decorators(base_price, decorators).

Input

base_price: The starting price.

decorators: The layers, in the order they wrap the price. Amounts may have decimals.

Output

Return the final price. Answers within 1e-6 are accepted.

Contraintes

0 ≤ base_price ≤ 1,000,000

0 ≤ number of decorators ≤ 100; 0 ≤ p ≤ 100, 0 ≤ a ≤ 100,000

Exemples

Exemple 1
Entrée :
base_price = 100
decorators = ["discount 10", "tax 8", "shipping 5"]

Sortie attendue :
expected = 102.2
Entrée :
long long base_price = 100;
std::vector<std::string> decorators = {"discount 10", "tax 8", "shipping 5"};

Sortie attendue :
double expected = 102.2;
Entrée :
long base_price = 100;
string[] decorators = new string[] {"discount 10", "tax 8", "shipping 5"};

Sortie attendue :
double expected = 102.2;

Explication

100 − 10% = 90, plus 8% tax = 97.2, plus 5 shipping = 102.2.

Exemple 2
Entrée :
base_price = 20
decorators = ["coupon 25", "shipping 4"]

Sortie attendue :
expected = 4.0
Entrée :
long long base_price = 20;
std::vector<std::string> decorators = {"coupon 25", "shipping 4"};

Sortie attendue :
double expected = 4.0;
Entrée :
long base_price = 20;
string[] decorators = new string[] {"coupon 25", "shipping 4"};

Sortie attendue :
double expected = 4.0;

Explication

The coupon would take the price below zero, so it stops at 0; shipping then makes it 4.

Comment l'aborder

Essayez d'abord seul, puis ouvrez les indices un par un.

Indice 1

Apply the layers strictly in the given order.

Indice 2

Percentages are taken from the current price, not the base price.

Indice 3

A coupon can never push the price below 0.

Complexité attendue

O(number of decorators) time, O(1) extra space

Références

Ce défi a été adapté pour CodeUtility. Suivez l'énoncé et les contraintes ci-dessus.

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