Problème
Afficher la traductionFind every triple of positive integers a < b < c for which a² + b² = c² and a + b + c = perimeter. Return each triple as [a, b, c], ordered by increasing a and then b. Do not include permutations of the same sides.
Implement pythagorean_triplets(perimeter).
Input
perimeter: The required sum of all three sides.
Output
Return a list of triples in the specified order.
Contraintes
3 ≤ perimeter ≤ 100,000. Return an empty list if no triangle qualifies.
Exemples
Entrée :
perimeter = 30
Sortie attendue :
expected = [
[5, 12, 13]
]
Entrée :
long long perimeter = 30;
Sortie attendue :
std::vector<std::vector<long long>> expected = {
{5, 12, 13}
};
Entrée :
long perimeter = 30;
Sortie attendue :
long[][] expected = new long[][] {
new long[] {5, 12, 13}
};
Explication
5 + 12 + 13 = 30 and 5² + 12² = 13². This is the only qualifying triple.
Entrée :
perimeter = 11
Sortie attendue :
expected = []
Entrée :
long long perimeter = 11;
Sortie attendue :
std::vector<std::vector<long long>> expected = {};
Entrée :
long perimeter = 11;
Sortie attendue :
long[][] expected = new long[][] {};
Explication
No increasing positive integer right-triangle triple sums to 11.
Références
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