Problème
Afficher la traductionConsider positive integers strictly below limit. Include a value if it is divisible by at least one nonzero factor. Count each included value once even if several factors divide it. Ignore zero factors. Factors [3, 5] give the familiar multiples-of-3-or-5 task.
Implement sum_of_multiples(limit, factors).
Input
limit: The exclusive upper bound.
factors: The factors whose multiples are eligible.
Output
Return the sum of distinct eligible positive integers.
Contraintes
0 ≤ limit ≤ 100,000. There may be 0 through 20 factors, each between 0 and 100,000. Duplicate factors are allowed.
Exemples
Entrée :
limit = 12
factors = [3, 5]
Sortie attendue :
expected = 33
Entrée :
long long limit = 12;
std::vector<long long> factors = {3, 5};
Sortie attendue :
long long expected = 33;
Entrée :
long limit = 12;
long[] factors = new long[] {3, 5};
Sortie attendue :
long expected = 33;
Explication
The included values are 3, 5, 6, 9, and 10. Their sum is 33.
Entrée :
limit = 10
factors = [2, 4]
Sortie attendue :
expected = 20
Entrée :
long long limit = 10;
std::vector<long long> factors = {2, 4};
Sortie attendue :
long long expected = 20;
Entrée :
long limit = 10;
long[] factors = new long[] {2, 4};
Sortie attendue :
long expected = 20;
Explication
Include 2, 4, 6, and 8. Values 4 and 8 are counted once despite matching both factors.
Références
Ce défi a été adapté pour CodeUtility. Suivez l'énoncé et les contraintes ci-dessus.