समस्या
अनुवाद दिखाएँAll machines start at time 0 and work independently. A machine with time t finishes one item after t seconds, another after 2t seconds, and so on. Find the earliest whole second when their combined production reaches the target.
Implement factory_machines(times, target).
Input
times: Seconds needed for one item on each machine.
target: The number of completed items required.
Output
Return the minimum elapsed seconds.
सीमाएँ
1 ≤ machines ≤ 200,000. Each time and the target are between 1 and 1,000,000,000. The answer fits signed 64-bit.
उदाहरण
इनपुट:
times = [2, 3]
target = 5
अपेक्षित आउटपुट:
expected = 6
इनपुट:
std::vector<long long> times = {2, 3};
long long target = 5;
अपेक्षित आउटपुट:
long long expected = 6;
इनपुट:
long[] times = new long[] {2, 3};
long target = 5;
अपेक्षित आउटपुट:
long expected = 6;
व्याख्या
At time 6 the machines have made 3 + 2 = 5 items. At time 5 they have made only 2 + 1 = 3.
इनपुट:
times = [4]
target = 3
अपेक्षित आउटपुट:
expected = 12
इनपुट:
std::vector<long long> times = {4};
long long target = 3;
अपेक्षित आउटपुट:
long long expected = 12;
इनपुट:
long[] times = new long[] {4};
long target = 3;
अपेक्षित आउटपुट:
long expected = 12;
व्याख्या
One machine completes its third item at 3 × 4 = 12 seconds.
संदर्भ
यह चुनौती CodeUtility के लिए अनुकूलित की गई है। ऊपर दिए गए स्टेटमेंट और सीमाओं का पालन करें।