समस्या
Sort the values into ascending order. For an odd number of values, take the middle one. For an even number, take the arithmetic mean of the two middle values. This challenge accepts only nonempty lists.
Implement median_number(numbers).
Input
numbers: The nonempty list of values.
Output
Return the median as a number; it may end in .5.
सीमाएँ
1 ≤ list length ≤ 100,000. Each value is an integer between −1,000,000,000 and 1,000,000,000.
उदाहरण
इनपुट:
numbers = [2, 8, 4, 10]
अपेक्षित आउटपुट:
expected = 6.0इनपुट:
std::vector<long long> numbers = {2, 8, 4, 10};
अपेक्षित आउटपुट:
double expected = 6.0;इनपुट:
long[] numbers = new long[] {2, 8, 4, 10};
अपेक्षित आउटपुट:
double expected = 6.0;व्याख्या
Sorted order is 2, 4, 8, 10. The middle pair averages to (4 + 8) / 2 = 6.
इनपुट:
numbers = [9, 1, 4]
अपेक्षित आउटपुट:
expected = 4.0इनपुट:
std::vector<long long> numbers = {9, 1, 4};
अपेक्षित आउटपुट:
double expected = 4.0;इनपुट:
long[] numbers = new long[] {9, 1, 4};
अपेक्षित आउटपुट:
double expected = 4.0;व्याख्या
Sorted order is 1, 4, 9, whose middle value is 4.
कैसे हल करें
पहले खुद कोशिश करें, फिर एक-एक करके संकेत खोलें।
संकेत 1
The median depends on sorted order, so the positions in the sorted list are what matter.
संकेत 2
After sorting, use the middle element for odd length, or combine the two middle elements for even length.
संकेत 3
Be careful to preserve halves when averaging two middle values, since the answer may end in .5.
अपेक्षित जटिलता
O(n log n) time, O(n) extra space
संदर्भ
यह चुनौती CodeUtility के लिए अनुकूलित की गई है। ऊपर दिए गए स्टेटमेंट और सीमाओं का पालन करें।