समस्या
The exponent is numerator / denominator. Raise base_value to that exponent and return the real-valued result. For example, an exponent of 1/3 gives the positive cube root.
Implement real_to_rational_power(base_value, numerator, denominator).
Input
base_value: The positive base.
numerator: The exponent numerator.
denominator: The exponent denominator.
Output
Return base_value raised to numerator / denominator.
सीमाएँ
0.1 ≤ base_value ≤ 100, with at most two decimal places. −6 ≤ numerator ≤ 6; 1 ≤ denominator ≤ 10. Answers are accepted within absolute or relative error 0.000001.
उदाहरण
इनपुट:
numerator = 1
base_value = 8.0
denominator = 3
अपेक्षित आउटपुट:
expected = 2.0इनपुट:
long long numerator = 1;
double base_value = 8.0;
long long denominator = 3;
अपेक्षित आउटपुट:
double expected = 2.0;इनपुट:
long numerator = 1;
double base_value = 8.0;
long denominator = 3;
अपेक्षित आउटपुट:
double expected = 2.0;व्याख्या
2 × 2 × 2 = 8, so the cube root is 2.
इनपुट:
numerator = -1
base_value = 16.0
denominator = 2
अपेक्षित आउटपुट:
expected = 0.25इनपुट:
long long numerator = -1;
double base_value = 16.0;
long long denominator = 2;
अपेक्षित आउटपुट:
double expected = 0.25;इनपुट:
long numerator = -1;
double base_value = 16.0;
long denominator = 2;
अपेक्षित आउटपुट:
double expected = 0.25;व्याख्या
The square root of 16 is 4, and the negative exponent takes its reciprocal, 1/4.
कैसे हल करें
पहले खुद कोशिश करें, फिर एक-एक करके संकेत खोलें।
संकेत 1
First turn the exponent fraction into a single real exponent.
संकेत 2
Then raise the positive base using a real-power operation.
संकेत 3
Make sure negative exponents produce reciprocals, and avoid mistakes with fractional roots.
अपेक्षित जटिलता
O(1) time, O(1) extra space
संदर्भ
यह चुनौती CodeUtility के लिए अनुकूलित की गई है। ऊपर दिए गए स्टेटमेंट और सीमाओं का पालन करें।