Unique Records

C# records compare by value: two records are equal when all their fields are equal, even if they are different objects. That makes removing duplicates easy.

Each record is written name,city. Trim spaces around both fields; after trimming, two records are equal when both fields match exactly (case matters).

Implement unique_records(records).

Input

records: The records, in order.

Output

Return the distinct records in the order they first appear, written name,city with the trimmed fields.

सीमाएँ

0 ≤ number of records ≤ 100,000

Each field has 1 to 30 characters and no commas

उदाहरण

इनपुट:
records = ["Ada,London", "Lin, Hanoi", "Ada , London"]

अपेक्षित आउटपुट:
expected = ["Ada,London", "Lin,Hanoi"]

इनपुट:
std::vector<std::string> records = {"Ada,London", "Lin, Hanoi", "Ada , London"};

अपेक्षित आउटपुट:
std::vector<std::string> expected = {"Ada,London", "Lin,Hanoi"};

इनपुट:
string[] records = new string[] {"Ada,London", "Lin, Hanoi", "Ada , London"};

अपेक्षित आउटपुट:
string[] expected = new string[] {"Ada,London", "Lin,Hanoi"};

इनपुट:
records = ["ada,Paris", "Ada,Paris"]

अपेक्षित आउटपुट:
expected = ["ada,Paris", "Ada,Paris"]

इनपुट:
std::vector<std::string> records = {"ada,Paris", "Ada,Paris"};

अपेक्षित आउटपुट:
std::vector<std::string> expected = {"ada,Paris", "Ada,Paris"};

इनपुट:
string[] records = new string[] {"ada,Paris", "Ada,Paris"};

अपेक्षित आउटपुट:
string[] expected = new string[] {"ada,Paris", "Ada,Paris"};

संदर्भ

यह चुनौती CodeUtility के लिए अनुकूलित की गई है। ऊपर दिए गए स्टेटमेंट और सीमाओं का पालन करें।

• Microsoft Learn, Records