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Linked List Operations

Simulate a linked list: add at either end, remove from the front or by value, and reverse it.

Cosa imparerai

  • Add and remove nodes at both ends
  • Remove the first node with a given value
  • Reverse the order of a list

Problema

Mostra traduzione

A linked list stores values in nodes that point to the next node, so adding or removing at the front is cheap. Simulate one that starts empty.

Process the operations in order:

  • push_front x: add x at the front.
  • push_back x: add x at the back.
  • pop_front: remove the first value (ignored when the list is empty).
  • remove x: remove the first node whose value is x, if there is one.
  • reverse: reverse the order of the nodes.

Implement linked_list_operations(operations).

Input

operations: The operations.

Output

Return the values in the list from front to back.

Vincoli

0 ≤ number of operations ≤ 10,000

−10^9 ≤ x ≤ 10^9

Esempi

Esempio 1
Input:
operations = ["push_back 2", "push_front 1", "push_back 3", "reverse"]

Output atteso:
expected = [3, 2, 1]
Input:
std::vector<std::string> operations = {"push_back 2", "push_front 1", "push_back 3", "reverse"};

Output atteso:
std::vector<long long> expected = {3, 2, 1};
Input:
string[] operations = new string[] {"push_back 2", "push_front 1", "push_back 3", "reverse"};

Output atteso:
long[] expected = new long[] {3, 2, 1};

Spiegazione

The list grows to 1 → 2 → 3, and reversing it gives [3, 2, 1].

Esempio 2
Input:
operations = ["push_back 5", "push_back 7", "push_back 5", "remove 5", "pop_front"]

Output atteso:
expected = [5]
Input:
std::vector<std::string> operations = {"push_back 5", "push_back 7", "push_back 5", "remove 5", "pop_front"};

Output atteso:
std::vector<long long> expected = {5};
Input:
string[] operations = new string[] {"push_back 5", "push_back 7", "push_back 5", "remove 5", "pop_front"};

Output atteso:
long[] expected = new long[] {5};

Spiegazione

remove takes out only the first 5, leaving 7 → 5; pop_front then removes 7: [5].

Come affrontarlo

Prova prima da solo, poi apri un suggerimento alla volta.

Suggerimento 1

A list type with cheap front and back inserts (std::list, LinkedList<T>, deque) does most of the work.

Suggerimento 2

remove deletes only the first match, and pop_front on an empty list does nothing.

Suggerimento 3

Reversing changes which end is the front for later pushes and pops.

Complessità attesa

O(n²) time, O(n) extra space

Riferimenti

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