Problema
The grid holds 1 for land and 0 for water. Land cells that touch up, down, left or right belong to the same island. Count the islands; a recursive flood fill is a natural approach.
Implement count_islands(grid).
Input
grid: A rectangular grid of 0s and 1s.
Output
Return the number of islands.
Vincoli
0 ≤ rows, columns ≤ 100
Esempi
Esempio 1
Input:
grid = [
[1, 1, 0, 0],
[0, 1, 0, 1],
[0, 0, 0, 1]
]
Output atteso:
expected = 2Input:
std::vector<std::vector<long long>> grid = {
{1, 1, 0, 0},
{0, 1, 0, 1},
{0, 0, 0, 1}
};
Output atteso:
long long expected = 2;Input:
long[][] grid = new long[][] {
new long[] {1, 1, 0, 0},
new long[] {0, 1, 0, 1},
new long[] {0, 0, 0, 1}
};
Output atteso:
long expected = 2;Spiegazione
The top-left group of 3 cells is one island; the two 1s on the right form a second: 2.
Esempio 2
Input:
grid = [
[1, 0, 1],
[0, 1, 0]
]
Output atteso:
expected = 3Input:
std::vector<std::vector<long long>> grid = {
{1, 0, 1},
{0, 1, 0}
};
Output atteso:
long long expected = 3;Input:
long[][] grid = new long[][] {
new long[] {1, 0, 1},
new long[] {0, 1, 0}
};
Output atteso:
long expected = 3;Spiegazione
Diagonal neighbors don't connect, so each 1 is its own island: 3.
Riferimenti
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