Problema
Count the pairs of different positions i < j in numbers where numbers[i] + numbers[j] equals target. Use two nested loops.
Implement count_pairs_with_sum(numbers, target).
Input
numbers: The list of integers. target: The sum to look for.
Output
Return the number of pairs.
Vincoli
0 ≤ length of numbers ≤ 500; -10,000 ≤ each number, target ≤ 10,000
Esempi
Input:
target = 6
numbers = [1, 5, 3, 3, 4]
Output atteso:
expected = 2
Input:
long long target = 6;
std::vector<long long> numbers = {1, 5, 3, 3, 4};
Output atteso:
long long expected = 2;
Input:
long target = 6;
long[] numbers = new long[] {1, 5, 3, 3, 4};
Output atteso:
long expected = 2;
Spiegazione
1 + 5, 3 + 3 (the two 3s at different positions) make 6: 2 pairs.
Input:
target = 4
numbers = [2, 2, 2]
Output atteso:
expected = 3
Input:
long long target = 4;
std::vector<long long> numbers = {2, 2, 2};
Output atteso:
long long expected = 3;
Input:
long target = 4;
long[] numbers = new long[] {2, 2, 2};
Output atteso:
long expected = 3;
Spiegazione
Every pair of the three 2s sums to 4: positions (0,1), (0,2), (1,2) = 3 pairs.
Riferimenti
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