Problema
Money in a savings account earns simple interest: each year adds rate percent of the original amount principal. Compute the total balance after years years.
Implement simple_interest_total(principal, rate, years).
Input
principal: The starting amount. rate: The yearly interest rate in percent. years: The number of whole years.
Output
Return principal + principal × rate / 100 × years.
Vincoli
0 ≤ principal ≤ 1,000,000; 0 ≤ rate ≤ 100; 0 ≤ years ≤ 100
Esempi
Input:
rate = 5.0
years = 2
principal = 1000.0
Output atteso:
expected = 1100.0Input:
double rate = 5.0;
long long years = 2;
double principal = 1000.0;
Output atteso:
double expected = 1100.0;Input:
double rate = 5.0;
long years = 2;
double principal = 1000.0;
Output atteso:
double expected = 1100.0;Spiegazione
Each year earns 1000 × 5% = 50, so two years add 100: 1000 + 100 = 1100.
Input:
rate = 0.0
years = 10
principal = 250.0
Output atteso:
expected = 250.0Input:
double rate = 0.0;
long long years = 10;
double principal = 250.0;
Output atteso:
double expected = 250.0;Input:
double rate = 0.0;
long years = 10;
double principal = 250.0;
Output atteso:
double expected = 250.0;Spiegazione
With a 0% rate nothing is added, so the balance stays 250.
Come affrontarlo
Prova prima da solo, poi apri un suggerimento alla volta.
Suggerimento 1
Simple interest uses the original principal every year, not the growing balance.
Suggerimento 2
Compute the yearly interest once, then multiply by the number of years.
Suggerimento 3
Make sure the final amount includes the starting principal as well as the accumulated interest.
Complessità attesa
O(1) time, O(1) extra space
Riferimenti
Questa sfida è adattata per CodeUtility. Segui la traccia e i vincoli sopra.