Problema
A payroll system treats every employee as an Employee with a WeeklyPay() method, and each kind of employee overrides it.
Each employee is written as:
salaried <annual>: earns annual / 52.hourly <rate> <hours>: earns rate × hours for the first 40 hours and 1.5 × rate for every hour beyond 40.commission <base> <rate> <sales>: earns base + rate × sales.
Implement weekly_payroll(employees).
Input
employees: The employees. Numbers may have decimals.
Output
Return the total weekly pay. Answers within 1e-6 are accepted.
Vincoli
0 ≤ number of employees ≤ 10,000
All numbers are between 0 and 10^7; hours ≤ 100
Esempi
Input:
employees = ["salaried 52000", "hourly 20 45"]
Output atteso:
expected = 1950.0Input:
std::vector<std::string> employees = {"salaried 52000", "hourly 20 45"};
Output atteso:
double expected = 1950.0;Input:
string[] employees = new string[] {"salaried 52000", "hourly 20 45"};
Output atteso:
double expected = 1950.0;Spiegazione
The salaried employee earns 52000 / 52 = 1000. The hourly one earns 20 × 40 + 30 × 5 = 950. Total 1950.
Input:
employees = ["commission 300 0.1 2500"]
Output atteso:
expected = 550.0Input:
std::vector<std::string> employees = {"commission 300 0.1 2500"};
Output atteso:
double expected = 550.0;Input:
string[] employees = new string[] {"commission 300 0.1 2500"};
Output atteso:
double expected = 550.0;Spiegazione
300 + 0.1 × 2500 = 550.
Come affrontarlo
Prova prima da solo, poi apri un suggerimento alla volta.
Suggerimento 1
Handle each employee type with its own formula.
Suggerimento 2
Hourly pay is normal for the first 40 hours and 1.5 times the rate after that.
Suggerimento 3
Keep decimals: salaries divided by 52 rarely give whole numbers.
Complessità attesa
O(number of employees) time, O(1) extra space
Riferimenti
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