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Categorical Cross-Entropy Loss

Measure the loss of a multi-class classifier from its predicted probabilities and the true classes.

このチャレンジで学べること

  • Score predicted probabilities against true classes
  • Average the loss over samples
  • Avoid log(0) with clipping

問題

翻訳を表示

A multi-class classifier outputs one probability per class (for example from softmax). Categorical cross-entropy punishes it for giving the correct class a low probability:

loss = -(ln(p₁) + ln(p₂) + … + ln(pₙ)) / n

where pᵢ is the probability the model gave to the correct class of sample i. To avoid ln(0), first raise any probability below 0.0000001 to 0.0000001.

Implement categorical_cross_entropy(probabilities, labels).

Input

probabilities: One row per sample, with one probability per class.

labels: The index of the correct class for each sample (0-based).

Output

Return the average loss as a decimal number.

制約

1 ≤ samples ≤ 1,000, 2 ≤ classes ≤ 100

0 ≤ each probability ≤ 1

0 ≤ labels[i] < number of classes

例

例 1
入力:
labels = [0, 1]
probabilities = [
    [0.7, 0.2, 0.1],
    [0.1, 0.8, 0.1]
]

期待される出力:
expected = 0.289909
入力:
std::vector<long long> labels = {0, 1};
std::vector<std::vector<double>> probabilities = {
    {0.7, 0.2, 0.1},
    {0.1, 0.8, 0.1}
};

期待される出力:
double expected = 0.289909;
入力:
long[] labels = new long[] {0, 1};
double[][] probabilities = new double[][] {
    new double[] {0.7, 0.2, 0.1},
    new double[] {0.1, 0.8, 0.1}
};

期待される出力:
double expected = 0.289909;

解説

The correct classes got 0.7 and 0.8: -(ln(0.7) + ln(0.8)) / 2 = -(-0.356675 - 0.223144) / 2 ≈ 0.289909.

例 2
入力:
labels = [1]
probabilities = [
    [1.0, 0.0]
]

期待される出力:
expected = 16.118096
入力:
std::vector<long long> labels = {1};
std::vector<std::vector<double>> probabilities = {
    {1.0, 0.0}
};

期待される出力:
double expected = 16.118096;
入力:
long[] labels = new long[] {1};
double[][] probabilities = new double[][] {
    new double[] {1.0, 0.0}
};

期待される出力:
double expected = 16.118096;

解説

The correct class got probability 0, which is raised to 0.0000001, so the loss is -ln(0.0000001) ≈ 16.118096: a confident wrong answer is punished hard.

参考資料

この課題はCodeUtility用に調整されています。上記の説明と制約に従ってください。

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