문제
번역본 보기Use any number of each supplied denomination to make amount exactly. Count combinations, not orderings: two arrangements using the same counts of each coin are the same way. Denominations are distinct and positive.
Implement coin_sums(amount, coins).
Input
amount: The total amount to make.
coins: The available distinct denominations.
Output
Return the number of unordered combinations.
제약 조건
0 ≤ amount ≤ 200. There are 0 through 10 distinct denominations, each from 1 through 200. All counts fit signed 64-bit. Amount 0 has one way: choose no coins.
예시
예시 1
입력:
coins = [1, 2]
amount = 4
예상 출력:
expected = 3입력:
std::vector<long long> coins = {1, 2};
long long amount = 4;
예상 출력:
long long expected = 3;입력:
long[] coins = new long[] {1, 2};
long amount = 4;
예상 출력:
long expected = 3;설명
The combinations are four 1s, two 1s with one 2, and two 2s.
예시 2
입력:
coins = [2]
amount = 3
예상 출력:
expected = 0입력:
std::vector<long long> coins = {2};
long long amount = 3;
예상 출력:
long long expected = 0;입력:
long[] coins = new long[] {2};
long amount = 3;
예상 출력:
long expected = 0;설명
Any sum of 2-valued coins is even, so 3 is impossible.
참고 자료
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