문제
Standardization rescales a feature so it has mean 0 and standard deviation 1, which many models (and gradient descent) work best with:
z = (x - mean) / std
Use the population standard deviation: std = √(Σ(x - mean)² / n). If std is 0 (all values equal), return 0 for every value.
Implement z_scores(values).
Input
values: The values of one feature.
Output
Return the z-score of each value, in the same order.
제약 조건
1 ≤ length ≤ 10,000
-1,000,000 ≤ each value ≤ 1,000,000
예시
입력:
values = [2.0, 4.0, 4.0, 4.0, 5.0, 5.0, 7.0, 9.0]
예상 출력:
expected = [-1.5, -0.5, -0.5, -0.5, 0.0, 0.0, 1.0, 2.0]
입력:
std::vector<double> values = {2.0, 4.0, 4.0, 4.0, 5.0, 5.0, 7.0, 9.0};
예상 출력:
std::vector<double> expected = {-1.5, -0.5, -0.5, -0.5, 0.0, 0.0, 1.0, 2.0};
입력:
double[] values = new double[] {2.0, 4.0, 4.0, 4.0, 5.0, 5.0, 7.0, 9.0};
예상 출력:
double[] expected = new double[] {-1.5, -0.5, -0.5, -0.5, 0.0, 0.0, 1.0, 2.0};
설명
The mean is 40 / 8 = 5 and the population standard deviation is √(32 / 8) = 2, so 2 → (2 - 5) / 2 = -1.5, 4 → -0.5, 5 → 0, 7 → 1 and 9 → 2. Result: [-1.5, -0.5, -0.5, -0.5, 0, 0, 1, 2].
입력:
values = [3.0, 3.0]
예상 출력:
expected = [0.0, 0.0]
입력:
std::vector<double> values = {3.0, 3.0};
예상 출력:
std::vector<double> expected = {0.0, 0.0};
입력:
double[] values = new double[] {3.0, 3.0};
예상 출력:
double[] expected = new double[] {0.0, 0.0};
설명
Both values equal the mean, so the standard deviation is 0 and both z-scores are 0.
참고 자료
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