Условие
The grid holds 1 for land and 0 for water. Land cells that touch up, down, left or right belong to the same island. Count the islands; a recursive flood fill is a natural approach.
Implement count_islands(grid).
Input
grid: A rectangular grid of 0s and 1s.
Output
Return the number of islands.
Ограничения
0 ≤ rows, columns ≤ 100
Примеры
Пример 1
Ввод:
grid = [
[1, 1, 0, 0],
[0, 1, 0, 1],
[0, 0, 0, 1]
]
Ожидаемый вывод:
expected = 2Ввод:
std::vector<std::vector<long long>> grid = {
{1, 1, 0, 0},
{0, 1, 0, 1},
{0, 0, 0, 1}
};
Ожидаемый вывод:
long long expected = 2;Ввод:
long[][] grid = new long[][] {
new long[] {1, 1, 0, 0},
new long[] {0, 1, 0, 1},
new long[] {0, 0, 0, 1}
};
Ожидаемый вывод:
long expected = 2;Пояснение
The top-left group of 3 cells is one island; the two 1s on the right form a second: 2.
Пример 2
Ввод:
grid = [
[1, 0, 1],
[0, 1, 0]
]
Ожидаемый вывод:
expected = 3Ввод:
std::vector<std::vector<long long>> grid = {
{1, 0, 1},
{0, 1, 0}
};
Ожидаемый вывод:
long long expected = 3;Ввод:
long[][] grid = new long[][] {
new long[] {1, 0, 1},
new long[] {0, 1, 0}
};
Ожидаемый вывод:
long expected = 3;Пояснение
Diagonal neighbors don't connect, so each 1 is its own island: 3.
Ссылки
Это задание адаптировано для CodeUtility. Следуйте условию и ограничениям выше.