Условие
C# records compare by value: two records are equal when all their fields are equal, even if they are different objects. That makes removing duplicates easy.
Each record is written name,city. Trim spaces around both fields; after trimming, two records are equal when both fields match exactly (case matters).
Implement unique_records(records).
Input
records: The records, in order.
Output
Return the distinct records in the order they first appear, written name,city with the trimmed fields.
Ограничения
0 ≤ number of records ≤ 100,000
Each field has 1 to 30 characters and no commas
Примеры
Ввод:
records = ["Ada,London", "Lin, Hanoi", "Ada , London"]
Ожидаемый вывод:
expected = ["Ada,London", "Lin,Hanoi"]
Ввод:
std::vector<std::string> records = {"Ada,London", "Lin, Hanoi", "Ada , London"};
Ожидаемый вывод:
std::vector<std::string> expected = {"Ada,London", "Lin,Hanoi"};
Ввод:
string[] records = new string[] {"Ada,London", "Lin, Hanoi", "Ada , London"};
Ожидаемый вывод:
string[] expected = new string[] {"Ada,London", "Lin,Hanoi"};
Пояснение
After trimming, the third record equals the first, so it is dropped: ["Ada,London", "Lin,Hanoi"].
Ввод:
records = ["ada,Paris", "Ada,Paris"]
Ожидаемый вывод:
expected = ["ada,Paris", "Ada,Paris"]
Ввод:
std::vector<std::string> records = {"ada,Paris", "Ada,Paris"};
Ожидаемый вывод:
std::vector<std::string> expected = {"ada,Paris", "Ada,Paris"};
Ввод:
string[] records = new string[] {"ada,Paris", "Ada,Paris"};
Ожидаемый вывод:
string[] expected = new string[] {"ada,Paris", "Ada,Paris"};
Пояснение
Case matters, so these two records are different: ["ada,Paris", "Ada,Paris"].
Как подступиться
Сначала попробуйте сами, затем открывайте подсказки по одной.
Подсказка 1
Trim both fields before comparing records.
Подсказка 2
A set of (name, city) pairs remembers which records you have seen.
Подсказка 3
Output each new record the first time it appears, in input order.
Ожидаемая сложность
O(total length) time, O(number of records) extra space
Ссылки
Это задание адаптировано для CodeUtility. Следуйте условию и ограничениям выше.