Problem
The observer pattern lets objects subscribe to a subject and get notified whenever something happens. Here, people subscribe to topics and every published event goes to everyone subscribed to its topic.
Each subscription is <person> <topic>. A repeated subscription has no extra effect. Then each event in events is a topic name: every subscriber of that topic receives one notification. Events on topics nobody follows are dropped.
Implement event_subscribers(subscriptions, events).
Input
subscriptions: "<person> <topic>" strings (names have no spaces).
events: Topic names, in publishing order.
Output
Return "<person>:<count>" for every person who has at least one subscription, sorted by name (ordinal character order).
Einschränkungen
1 ≤ number of subscriptions ≤ 10,000
0 ≤ number of events ≤ 100,000
Beispiele
Eingabe:
events = ["news", "sports", "weather"]
subscriptions = ["bob sports", "alice news", "alice sports"]
Erwartete Ausgabe:
expected = ["alice:2", "bob:1"]Eingabe:
std::vector<std::string> events = {"news", "sports", "weather"};
std::vector<std::string> subscriptions = {"bob sports", "alice news", "alice sports"};
Erwartete Ausgabe:
std::vector<std::string> expected = {"alice:2", "bob:1"};Eingabe:
string[] events = new string[] {"news", "sports", "weather"};
string[] subscriptions = new string[] {"bob sports", "alice news", "alice sports"};
Erwartete Ausgabe:
string[] expected = new string[] {"alice:2", "bob:1"};Erläuterung
alice follows news and sports, so she gets both events; bob only gets sports; nobody follows weather: ["alice:2", "bob:1"].
Eingabe:
events = []
subscriptions = ["zoe tech", "zoe tech"]
Erwartete Ausgabe:
expected = ["zoe:0"]Eingabe:
std::vector<std::string> events = {};
std::vector<std::string> subscriptions = {"zoe tech", "zoe tech"};
Erwartete Ausgabe:
std::vector<std::string> expected = {"zoe:0"};Eingabe:
string[] events = new string[] {};
string[] subscriptions = new string[] {"zoe tech", "zoe tech"};
Erwartete Ausgabe:
string[] expected = new string[] {"zoe:0"};Erläuterung
The repeated subscription counts once, and no events were published: ["zoe:0"].
So gehst du vor
Versuch es zuerst allein und öffne dann einen Hinweis nach dem anderen.
Hinweis 1
Group subscribers by topic so each event finds its audience quickly.
Hinweis 2
Use a set per topic so a repeated subscription counts once.
Hinweis 3
Everyone who subscribed appears in the result, even with zero notifications.
Erwartete Komplexität
O(subscriptions + events × subscribers per topic) time, O(subscriptions) extra space
Referenzen
Diese Aufgabe wurde für CodeUtility angepasst. Beachte die oben genannten Vorgaben und Einschränkungen.