Problem
The factory method pattern hides how objects are created: you ask the factory for a shape by name and get back an object that knows how to compute its own area.
Each description is a shape name followed by its numbers, separated by spaces:
circle r: area π·r²square s: area s²rectangle w h: area w·htriangle b h: area b·h / 2
Implement shape_factory_areas(shapes).
Input
shapes: The descriptions. Numbers may have decimals.
Output
Return the area of each shape, in order. Answers within 1e-6 are accepted.
Einschränkungen
1 ≤ number of shapes ≤ 1,000
0 < every number ≤ 1,000
Beispiele
Eingabe:
shapes = ["square 3", "rectangle 2 5", "triangle 4 3"]
Erwartete Ausgabe:
expected = [9.0, 10.0, 6.0]
Eingabe:
std::vector<std::string> shapes = {"square 3", "rectangle 2 5", "triangle 4 3"};
Erwartete Ausgabe:
std::vector<double> expected = {9.0, 10.0, 6.0};
Eingabe:
string[] shapes = new string[] {"square 3", "rectangle 2 5", "triangle 4 3"};
Erwartete Ausgabe:
double[] expected = new double[] {9.0, 10.0, 6.0};
Erläuterung
3² = 9, 2·5 = 10 and 4·3/2 = 6.
Eingabe:
shapes = ["circle 1"]
Erwartete Ausgabe:
expected = [3.141592653589793]
Eingabe:
std::vector<std::string> shapes = {"circle 1"};
Erwartete Ausgabe:
std::vector<double> expected = {3.141592653589793};
Eingabe:
string[] shapes = new string[] {"circle 1"};
Erwartete Ausgabe:
double[] expected = new double[] {3.141592653589793};
Erläuterung
π·1² = π ≈ 3.141593.
So gehst du vor
Versuch es zuerst allein und öffne dann einen Hinweis nach dem anderen.
Hinweis 1
Read the first word to know which shape to build.
Hinweis 2
Map each shape name to its area formula.
Hinweis 3
Use π from your language's math library and keep full precision.
Erwartete Komplexität
O(number of shapes) time, O(number of shapes) extra space
Referenzen
Diese Aufgabe wurde für CodeUtility angepasst. Beachte die oben genannten Vorgaben und Einschränkungen.