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Nearest Smaller Value to the Left

For each number, find the closest earlier position containing a strictly smaller number.

問題

For each number, find the closest earlier position containing a strictly smaller number. Equal numbers do not qualify. Positions start at 1; use 0 when there is no smaller number to the left.

Implement nearest_smaller_value(numbers).

Input

numbers: Numbers in their original order.

Output

Return one earlier position (or 0) for every input value.

制約

0…200,000 integers, each between −1,000,000,000 and 1,000,000,000. Empty input returns an empty list.

例

例 1
入力:
numbers = [4, 2, 5, 3]

期待される出力:
expected = [0, 0, 2, 2]
入力:
std::vector<long long> numbers = {4, 2, 5, 3};

期待される出力:
std::vector<long long> expected = {0, 0, 2, 2};
入力:
long[] numbers = new long[] {4, 2, 5, 3};

期待される出力:
long[] expected = new long[] {0, 0, 2, 2};

解説

4 has no earlier value and 2 has no smaller earlier value. Both 5 and 3 find the value 2 at position 2.

例 2
入力:
numbers = [2, 2, 2]

期待される出力:
expected = [0, 0, 0]
入力:
std::vector<long long> numbers = {2, 2, 2};

期待される出力:
std::vector<long long> expected = {0, 0, 0};
入力:
long[] numbers = new long[] {2, 2, 2};

期待される出力:
long[] expected = new long[] {0, 0, 0};

解説

Earlier equal values are not strictly smaller. Every answer is 0.

参考資料

この課題はCodeUtility用に調整されています。上記の説明と制約に従ってください。

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