問題
翻訳を表示The exponent is numerator / denominator. Raise base_value to that exponent and return the real-valued result. For example, an exponent of 1/3 gives the positive cube root.
Implement real_to_rational_power(base_value, numerator, denominator).
Input
base_value: The positive base.
numerator: The exponent numerator.
denominator: The exponent denominator.
Output
Return base_value raised to numerator / denominator.
制約
0.1 ≤ base_value ≤ 100, with at most two decimal places. −6 ≤ numerator ≤ 6; 1 ≤ denominator ≤ 10. Answers are accepted within absolute or relative error 0.000001.
例
入力:
numerator = 1
base_value = 8.0
denominator = 3
期待される出力:
expected = 2.0
入力:
long long numerator = 1;
double base_value = 8.0;
long long denominator = 3;
期待される出力:
double expected = 2.0;
入力:
long numerator = 1;
double base_value = 8.0;
long denominator = 3;
期待される出力:
double expected = 2.0;
解説
2 × 2 × 2 = 8, so the cube root is 2.
入力:
numerator = -1
base_value = 16.0
denominator = 2
期待される出力:
expected = 0.25
入力:
long long numerator = -1;
double base_value = 16.0;
long long denominator = 2;
期待される出力:
double expected = 0.25;
入力:
long numerator = -1;
double base_value = 16.0;
long denominator = 2;
期待される出力:
double expected = 0.25;
解説
The square root of 16 is 4, and the negative exponent takes its reciprocal, 1/4.
参考資料
この課題はCodeUtility用に調整されています。上記の説明と制約に従ってください。