問題
A to-do app keeps tasks in a typed collection such as List<T>. Each task has a title and a done flag.
Start with an empty list and process the operations, each a command and a title (the title is everything after the first space):
add <title>: add a pending task at the end, unless a task with that title already exists.done <title>: mark that task as done (no effect if it does not exist).remove <title>: delete that task (no effect if it does not exist).
Implement todo_list(operations).
Input
operations: The operations. Titles may contain spaces and are compared exactly.
Output
Return the titles of the tasks that are not done, in the order they were added.
制約
0 ≤ number of operations ≤ 10,000
Titles have 1 to 50 characters
例
入力:
operations = ["add Buy milk", "add Write report", "done Buy milk", "add Call Ada"]
期待される出力:
expected = ["Write report", "Call Ada"]
入力:
std::vector<std::string> operations = {"add Buy milk", "add Write report", "done Buy milk", "add Call Ada"};
期待される出力:
std::vector<std::string> expected = {"Write report", "Call Ada"};
入力:
string[] operations = new string[] {"add Buy milk", "add Write report", "done Buy milk", "add Call Ada"};
期待される出力:
string[] expected = new string[] {"Write report", "Call Ada"};
解説
Buy milk is done, so only the other two remain, in the order they were added: ["Write report", "Call Ada"].
入力:
operations = ["add Gym", "add Gym", "remove Gym", "done Gym"]
期待される出力:
expected = []
入力:
std::vector<std::string> operations = {"add Gym", "add Gym", "remove Gym", "done Gym"};
期待される出力:
std::vector<std::string> expected = {};
入力:
string[] operations = new string[] {"add Gym", "add Gym", "remove Gym", "done Gym"};
期待される出力:
string[] expected = new string[] {};
解説
The second add is ignored because Gym already exists; removing it leaves nothing, and done on a missing task does nothing: [].
解き方のヒント
まずは自分で考えてから、ヒントを 1 つずつ開いてみましょう。
ヒント 1
Store each task as a small record of title and done.
ヒント 2
Look a task up by its exact title before adding, completing or removing it.
ヒント 3
At the end keep only the tasks that are not done, in insertion order.
目安の計算量
O(n²) time, O(n) extra space
参考資料
この課題はCodeUtility用に調整されています。上記の説明と制約に従ってください。