문제
Every person shakes hands once with every other person. A handshake between A and B is the same event as one between B and A. Nobody shakes their own hand.
Implement handshake_count(people).
Input
people: The number of people.
Output
Return the total number of distinct handshakes.
제약 조건
0 ≤ people ≤ 1,000,000,000. The answer fits a signed 64-bit integer.
예시
입력:
people = 4
예상 출력:
expected = 6
입력:
long long people = 4;
예상 출력:
long long expected = 6;
입력:
long people = 4;
예상 출력:
long expected = 6;
설명
The pairs are AB, AC, AD, BC, BD, and CD: six handshakes.
입력:
people = 1
예상 출력:
expected = 0
입력:
long long people = 1;
예상 출력:
long long expected = 0;
입력:
long people = 1;
예상 출력:
long expected = 0;
설명
One person has nobody else to greet.
접근 방법
먼저 스스로 풀어 본 뒤 힌트를 하나씩 열어 보세요.
힌트 1
Each handshake is just an unordered pair of distinct people.
힌트 2
Count how many pairs can be formed from all people without double-counting.
힌트 3
Be careful that zero or one person means no handshakes at all.
예상 복잡도
O(1) time, O(1) extra space
참고 자료
이 문제는 CodeUtility에 맞게 수정되었습니다. 위의 설명과 제한 조건을 따르세요.