Problema
Bars of width 1 have the given heights. After rain, water collects above each bar up to the lower of the tallest bars on its left and right. Compute the total trapped water. An O(n) two-pointer solution is expected.
Implement trapped_water(heights).
Input
heights: Bar heights from left to right.
Output
Return the total units of water.
Restrições
0 ≤ length ≤ 200,000; 0 ≤ height ≤ 100,000
Exemplos
Entrada:
heights = [0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1]
Saída esperada:
expected = 6
Entrada:
std::vector<long long> heights = {0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1};
Saída esperada:
long long expected = 6;
Entrada:
long[] heights = new long[] {0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1};
Saída esperada:
long expected = 6;
Explicação
Water fills the dips: 1 + 1 + 2 + 1 + 1 = 6 units.
Entrada:
heights = [3, 2, 1]
Saída esperada:
expected = 0
Entrada:
std::vector<long long> heights = {3, 2, 1};
Saída esperada:
long long expected = 0;
Entrada:
long[] heights = new long[] {3, 2, 1};
Saída esperada:
long expected = 0;
Explicação
Heights only go down, so water runs off: 0.
Referências
Este desafio foi adaptado para o CodeUtility. Siga o enunciado e as restrições acima.