โจทย์
A subsequence is formed by deleting zero or more elements while preserving the order of the remaining elements. Find the longest length shared by two arrays. Matching elements need not be adjacent. Return only the length, since several equally long subsequences may exist.
Implement longest_common_subsequence_length(first, second).
Input
first: The first sequence.
second: The second sequence.
Output
Return the maximum common subsequence length. If either array is empty, return 0.
เงื่อนไข
Each array has 0…1,000 integers between −1,000,000,000 and 1,000,000,000. Duplicates are allowed.
ตัวอย่าง
อินพุต:
first = [1, 3, 2, 4]
second = [3, 1, 2, 4]
ผลลัพธ์ที่คาดหวัง:
expected = 3
อินพุต:
std::vector<long long> first = {1, 3, 2, 4};
std::vector<long long> second = {3, 1, 2, 4};
ผลลัพธ์ที่คาดหวัง:
long long expected = 3;
อินพุต:
long[] first = new long[] {1, 3, 2, 4};
long[] second = new long[] {3, 1, 2, 4};
ผลลัพธ์ที่คาดหวัง:
long expected = 3;
คำอธิบาย
Both contain [1, 2, 4] in that order, after deleting one value. The original arrays differ, so a length-four match is impossible.
อินพุต:
first = [1, 2]
second = [3, 4]
ผลลัพธ์ที่คาดหวัง:
expected = 0
อินพุต:
std::vector<long long> first = {1, 2};
std::vector<long long> second = {3, 4};
ผลลัพธ์ที่คาดหวัง:
long long expected = 0;
อินพุต:
long[] first = new long[] {1, 2};
long[] second = new long[] {3, 4};
ผลลัพธ์ที่คาดหวัง:
long expected = 0;
คำอธิบาย
The arrays have no shared value, so their only common subsequence is empty.
แหล่งอ้างอิง
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