Problem
Compare two DNA strings position by position and count the differences. Only characters at the same position are compared; do not insert, delete, or shift characters. No biology knowledge is needed.
Implement hamming_distance(first, second).
Input
first: The first DNA string.
second: The equal-length second DNA string.
Output
Return the number of positions with different characters.
Einschränkungen
Both strings have the same length, from 0 to 100,000. Characters are uppercase A, C, G, or T.
Beispiele
Eingabe:
first = "ACCT"
second = "AGCA"
Erwartete Ausgabe:
expected = 2
Eingabe:
std::string first = "ACCT";
std::string second = "AGCA";
Erwartete Ausgabe:
long long expected = 2;
Eingabe:
string first = "ACCT";
string second = "AGCA";
Erwartete Ausgabe:
long expected = 2;
Erläuterung
The second position is C versus G and the fourth is T versus A. The first and third match: two differences.
Eingabe:
first = "GATT"
second = "GATT"
Erwartete Ausgabe:
expected = 0
Eingabe:
std::string first = "GATT";
std::string second = "GATT";
Erwartete Ausgabe:
long long expected = 0;
Eingabe:
string first = "GATT";
string second = "GATT";
Erwartete Ausgabe:
long expected = 0;
Erläuterung
All four positions match, so no differences are counted.
Referenzen
Diese Aufgabe wurde für CodeUtility angepasst. Beachte die oben genannten Vorgaben und Einschränkungen.