Problem
Represent a fraction as [numerator, denominator]. Apply operation to first and second: add, subtract, multiply, or divide. For absolute, use only first. For power, raise first to the integer exponent and ignore second. Return lowest terms with a positive denominator. Normalize zero to [0, 1]. All divisions and negative powers in valid inputs are defined.
Implement rational_arithmetic(operation, first, second, exponent).
Input
operation: The operation name.
first: Two integers representing the first fraction.
second: Two integers representing the second fraction; use [0, 1] when unused.
exponent: The exponent for power; use 0 for other operations.
Output
Return [numerator, denominator] in reduced form with a positive denominator.
Einschränkungen
operation is add, subtract, multiply, divide, absolute, or power. Both fraction components have magnitude at most 100; denominators are nonzero. −6 ≤ exponent ≤ 6. For divide, second has nonzero numerator. For a negative power, first has nonzero numerator. The 0th power is [1, 1], including 0⁰ by this task’s convention. Values fit signed 64-bit.
Beispiele
Eingabe:
first = [1, 6]
second = [1, 4]
exponent = 0
operation = "add"
Erwartete Ausgabe:
expected = [5, 12]
Eingabe:
std::vector<long long> first = {1, 6};
std::vector<long long> second = {1, 4};
long long exponent = 0;
std::string operation = "add";
Erwartete Ausgabe:
std::vector<long long> expected = {5, 12};
Eingabe:
long[] first = new long[] {1, 6};
long[] second = new long[] {1, 4};
long exponent = 0;
string operation = "add";
Erwartete Ausgabe:
long[] expected = new long[] {5, 12};
Erläuterung
1/6 + 1/4 = 2/12 + 3/12 = 5/12, already reduced.
Eingabe:
first = [2, 3]
second = [0, 1]
exponent = -2
operation = "power"
Erwartete Ausgabe:
expected = [9, 4]
Eingabe:
std::vector<long long> first = {2, 3};
std::vector<long long> second = {0, 1};
long long exponent = -2;
std::string operation = "power";
Erwartete Ausgabe:
std::vector<long long> expected = {9, 4};
Eingabe:
long[] first = new long[] {2, 3};
long[] second = new long[] {0, 1};
long exponent = -2;
string operation = "power";
Erwartete Ausgabe:
long[] expected = new long[] {9, 4};
Erläuterung
A negative exponent inverts the fraction: (2/3)⁻² = (3/2)² = 9/4.
So gehst du vor
Versuch es zuerst allein und öffne dann einen Hinweis nach dem anderen.
Hinweis 1
Convert each fraction to a common representation and combine the numerators according to the chosen operation.
Hinweis 2
After the operation, reduce the result by dividing by the greatest common divisor and make the denominator positive.
Hinweis 3
Watch special cases like zero results, absolute value, and the power rule’s zero and negative exponents.
Erwartete Komplexität
O(log n) time, O(1) extra space
Referenzen
Diese Aufgabe wurde für CodeUtility angepasst. Beachte die oben genannten Vorgaben und Einschränkungen.